Optimal. Leaf size=76 \[ -\frac{2 a^2 (e x)^{m+3}}{e^3 (m+3)}-\frac{2 a^3 (e x)^{m+4}}{e^4 (m+4)}+\frac{2 a (e x)^{m+2}}{e^2 (m+2)}+\frac{2 (e x)^{m+1}}{e (m+1)} \]
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Rubi [A] time = 0.0259322, antiderivative size = 76, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.053, Rules used = {75} \[ -\frac{2 a^2 (e x)^{m+3}}{e^3 (m+3)}-\frac{2 a^3 (e x)^{m+4}}{e^4 (m+4)}+\frac{2 a (e x)^{m+2}}{e^2 (m+2)}+\frac{2 (e x)^{m+1}}{e (m+1)} \]
Antiderivative was successfully verified.
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Rule 75
Rubi steps
\begin{align*} \int (e x)^m (2-2 a x) (1+a x)^2 \, dx &=\int \left (2 (e x)^m+\frac{2 a (e x)^{1+m}}{e}-\frac{2 a^2 (e x)^{2+m}}{e^2}-\frac{2 a^3 (e x)^{3+m}}{e^3}\right ) \, dx\\ &=\frac{2 (e x)^{1+m}}{e (1+m)}+\frac{2 a (e x)^{2+m}}{e^2 (2+m)}-\frac{2 a^2 (e x)^{3+m}}{e^3 (3+m)}-\frac{2 a^3 (e x)^{4+m}}{e^4 (4+m)}\\ \end{align*}
Mathematica [A] time = 0.0576997, size = 83, normalized size = 1.09 \[ \frac{\left (\frac{2 (2 m+5) x \left (m \left (3 a^2 x^2+8 a x+5\right )+2 a^2 x^2+(a m x+m)^2+6 a x+6\right )}{(m+1) (m+2) (m+3)}-2 x (a x+1)^3\right ) (e x)^m}{m+4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.004, size = 143, normalized size = 1.9 \begin{align*} -2\,{\frac{ \left ( ex \right ) ^{m} \left ({a}^{3}{m}^{3}{x}^{3}+6\,{a}^{3}{m}^{2}{x}^{3}+11\,{a}^{3}m{x}^{3}+{a}^{2}{m}^{3}{x}^{2}+6\,{a}^{3}{x}^{3}+7\,{a}^{2}{m}^{2}{x}^{2}+14\,{a}^{2}m{x}^{2}-a{m}^{3}x+8\,{a}^{2}{x}^{2}-8\,a{m}^{2}x-19\,amx-{m}^{3}-12\,ax-9\,{m}^{2}-26\,m-24 \right ) x}{ \left ( 4+m \right ) \left ( 3+m \right ) \left ( 2+m \right ) \left ( 1+m \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.1812, size = 286, normalized size = 3.76 \begin{align*} -\frac{2 \,{\left ({\left (a^{3} m^{3} + 6 \, a^{3} m^{2} + 11 \, a^{3} m + 6 \, a^{3}\right )} x^{4} +{\left (a^{2} m^{3} + 7 \, a^{2} m^{2} + 14 \, a^{2} m + 8 \, a^{2}\right )} x^{3} -{\left (a m^{3} + 8 \, a m^{2} + 19 \, a m + 12 \, a\right )} x^{2} -{\left (m^{3} + 9 \, m^{2} + 26 \, m + 24\right )} x\right )} \left (e x\right )^{m}}{m^{4} + 10 \, m^{3} + 35 \, m^{2} + 50 \, m + 24} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.895672, size = 668, normalized size = 8.79 \begin{align*} \begin{cases} \frac{- 2 a^{3} \log{\left (x \right )} + \frac{2 a^{2}}{x} - \frac{a}{x^{2}} - \frac{2}{3 x^{3}}}{e^{4}} & \text{for}\: m = -4 \\\frac{- 2 a^{3} x - 2 a^{2} \log{\left (x \right )} - \frac{2 a}{x} - \frac{1}{x^{2}}}{e^{3}} & \text{for}\: m = -3 \\\frac{- a^{3} x^{2} - 2 a^{2} x + 2 a \log{\left (x \right )} - \frac{2}{x}}{e^{2}} & \text{for}\: m = -2 \\\frac{- \frac{2 a^{3} x^{3}}{3} - a^{2} x^{2} + 2 a x + 2 \log{\left (x \right )}}{e} & \text{for}\: m = -1 \\- \frac{2 a^{3} e^{m} m^{3} x^{4} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} - \frac{12 a^{3} e^{m} m^{2} x^{4} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} - \frac{22 a^{3} e^{m} m x^{4} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} - \frac{12 a^{3} e^{m} x^{4} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} - \frac{2 a^{2} e^{m} m^{3} x^{3} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} - \frac{14 a^{2} e^{m} m^{2} x^{3} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} - \frac{28 a^{2} e^{m} m x^{3} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} - \frac{16 a^{2} e^{m} x^{3} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} + \frac{2 a e^{m} m^{3} x^{2} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} + \frac{16 a e^{m} m^{2} x^{2} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} + \frac{38 a e^{m} m x^{2} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} + \frac{24 a e^{m} x^{2} x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} + \frac{2 e^{m} m^{3} x x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} + \frac{18 e^{m} m^{2} x x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} + \frac{52 e^{m} m x x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} + \frac{48 e^{m} x x^{m}}{m^{4} + 10 m^{3} + 35 m^{2} + 50 m + 24} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.19875, size = 309, normalized size = 4.07 \begin{align*} -\frac{2 \,{\left (a^{3} m^{3} x^{4} x^{m} e^{m} + 6 \, a^{3} m^{2} x^{4} x^{m} e^{m} + a^{2} m^{3} x^{3} x^{m} e^{m} + 11 \, a^{3} m x^{4} x^{m} e^{m} + 7 \, a^{2} m^{2} x^{3} x^{m} e^{m} + 6 \, a^{3} x^{4} x^{m} e^{m} - a m^{3} x^{2} x^{m} e^{m} + 14 \, a^{2} m x^{3} x^{m} e^{m} - 8 \, a m^{2} x^{2} x^{m} e^{m} + 8 \, a^{2} x^{3} x^{m} e^{m} - m^{3} x x^{m} e^{m} - 19 \, a m x^{2} x^{m} e^{m} - 9 \, m^{2} x x^{m} e^{m} - 12 \, a x^{2} x^{m} e^{m} - 26 \, m x x^{m} e^{m} - 24 \, x x^{m} e^{m}\right )}}{m^{4} + 10 \, m^{3} + 35 \, m^{2} + 50 \, m + 24} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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